CP 3 Practice Questions
These CP 3 practice questions focus on theory, design logic, calculations, criteria interpretation, current distribution, and troubleshooting judgment.
Study Focus
CP 3-level study requires moving beyond definitions. Focus on why criteria apply, how calculations are built, how current distributes, and how field data supports or fails to support conclusions.
Practice Questions
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A pipeline has an ON potential of −1,120 mVCSE and an instant-off potential of −790 mVCSE. What is the best interpretation?
- The ON value alone proves the pipeline satisfies a polarized −850 mVCSE criterion
- The instant-off value suggests the polarized potential does not satisfy −850 mVCSE
- The reference electrode is unnecessary
- The pipeline is overprotected everywhere
Answer: B. If the criterion requires a polarized potential, the instant-off value is the relevant value and it is less negative than −850 mVCSE.
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A structure has an instant-off potential of −760 mVCSE and a depolarized potential of −640 mVCSE. What is the depolarization?
- 120 mV
- 640 mV
- 760 mV
- 1,400 mV
Answer: A. The magnitude of the change is 120 mV.
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A rectifier operates at 48 volts and 4 amps. What is the effective circuit resistance?
- 192 ohms
- 12 ohms
- 0.083 ohms
- 52 ohms
Answer: B. R = V ÷ I = 48 ÷ 4 = 12 ohms.
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A coated structure has 20,000 ft² total area and 2 percent coating breakdown. What exposed area is assumed?
- 40 ft²
- 400 ft²
- 2,000 ft²
- 10,000 ft²
Answer: B. 20,000 × 0.02 = 400 ft².
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Using 400 ft² exposed area and 3 mA/ft², what current is required?
- 120 mA
- 1,200 mA
- 12,000 mA
- 0.013 mA
Answer: B. 400 × 3 = 1,200 mA, or 1.2 amps.
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Why is the 100 mV polarization criterion not a universal fallback?
- Because it requires valid data and must be permitted by the governing requirement
- Because it never applies to CP
- Because it does not require current interruption or documentation
- Because reference electrodes are not used
Answer: A. The criterion must be allowed and supported by valid polarization or depolarization data.
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A galvanic anode has 20 amp-years usable capacity and discharges 0.5 amps. What is estimated life?
- 10 years
- 20 years
- 40 years
- 100 years
Answer: C. Life = 20 ÷ 0.5 = 40 years.
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What condition can increase CP current requirement over time?
- Coating deterioration
- Improved coating isolation from electrolyte
- Reduced exposed metal area
- Removal of unintended continuity
Answer: A. Coating deterioration increases exposed area and current demand.
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Why can a low-resistance groundbed still be a poor design?
- Because current distribution and interference risk also matter
- Because low resistance prevents all current flow
- Because rectifiers only work at infinite resistance
- Because anodes cannot discharge current in soil
Answer: A. Low resistance is useful, but current distribution and interference must also be evaluated.
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What is the most defensible response to conflicting CP data?
- Select the most favorable reading
- Average unrelated readings
- Classify readings by structure, test condition, reference electrode, and criterion
- Ignore readings that fail
Answer: C. Conflicting data must be organized by what was measured and which criterion it supports.